Hobbywing Tunalyzer
#31
Tech Elite
iTrader: (51)
More food for thought: same motor, Hobbywing G4 13.5 in both these tests.
Only difference between these 2 runs is the Tunalyzer test voltage was changed from 7.4 to 3.4. No idea why the current would be higher on the lower voltage. Also, why 3.4? 1S voltage is 3.7.
Only difference between these 2 runs is the Tunalyzer test voltage was changed from 7.4 to 3.4. No idea why the current would be higher on the lower voltage. Also, why 3.4? 1S voltage is 3.7.
Edit: To expand further, if the power is the same for 3.4v and for 7.2v and power = torque x rpm, but the rpm drops, then torque needs to increase. Increasing torque will increase current. But the analysers are measuring unloaded so torque should be near zero. Maybe your bearings are bad?
Last edited by trilerian; 05-04-2023 at 07:27 AM.
#32
R/C Tech Elite Member
iTrader: (9)
More food for thought: same motor, Hobbywing G4 13.5 in both these tests.
Only difference between these 2 runs is the Tunalyzer test voltage was changed from 7.4 to 3.4. No idea why the current would be higher on the lower voltage. Also, why 3.4? 1S voltage is 3.7.
Only difference between these 2 runs is the Tunalyzer test voltage was changed from 7.4 to 3.4. No idea why the current would be higher on the lower voltage. Also, why 3.4? 1S voltage is 3.7.
#33
More food for thought: same motor, Hobbywing G4 13.5 in both these tests.
Only difference between these 2 runs is the Tunalyzer test voltage was changed from 7.4 to 3.4. No idea why the current would be higher on the lower voltage. Also, why 3.4? 1S voltage is 3.7.
Only difference between these 2 runs is the Tunalyzer test voltage was changed from 7.4 to 3.4. No idea why the current would be higher on the lower voltage. Also, why 3.4? 1S voltage is 3.7.
8⁸
#35
Tech Champion
iTrader: (2)
I asked a question similar to this a few years ago. The answer was it had to do with the power output of the motor. It stays the same no matter the input voltage.
Edit: To expand further, if the power is the same for 3.4v and for 7.2v and power = torque x rpm, but the rpm drops, then torque needs to increase. Increasing torque will increase current. But the analysers are measuring unloaded so torque should be near zero. Maybe your bearings are bad?
Edit: To expand further, if the power is the same for 3.4v and for 7.2v and power = torque x rpm, but the rpm drops, then torque needs to increase. Increasing torque will increase current. But the analysers are measuring unloaded so torque should be near zero. Maybe your bearings are bad?
I doubt the bearings are bad, this motor has only done 2 events and it podiumed both times.
#38
OffRoadJunkie
It's just not that simple all the time. If you take e.g. a LiPo Charger and the settings you've selected require let's say 240W from the PSU... then yes, if your PSU only delivers 12V than your charger will draw 20A, while at 24V only 10A (assuming the charger can take both input voltages).
So note: this "the fewer the voltage, the higher the current" is only valid for a fixed electrical power. But not all devices have such fixed power. Some will simply produce/draw less overall power, when you cut the voltage down.
If we take a simple resistor of 1 Ohm and supply 10V, you'll get a current of 10A through it. Same resistor with only 5V? No, not 20A but only 5A. So half the voltage equals half the amps here.
So in layman's terms you need the voltage (often compared to water "pressure") to push a certain current (compared to amount of water flowing per second) past a resistor (obstacle). If you don't supply enough pressure, you get less flow.
It's just not that simple all the time. If you take e.g. a LiPo Charger and the settings you've selected require let's say 240W from the PSU... then yes, if your PSU only delivers 12V than your charger will draw 20A, while at 24V only 10A (assuming the charger can take both input voltages).
So note: this "the fewer the voltage, the higher the current" is only valid for a fixed electrical power. But not all devices have such fixed power. Some will simply produce/draw less overall power, when you cut the voltage down.
If we take a simple resistor of 1 Ohm and supply 10V, you'll get a current of 10A through it. Same resistor with only 5V? No, not 20A but only 5A. So half the voltage equals half the amps here.
So in layman's terms you need the voltage (often compared to water "pressure") to push a certain current (compared to amount of water flowing per second) past a resistor (obstacle). If you don't supply enough pressure, you get less flow.
Last edited by DirkW; 05-05-2023 at 03:54 AM.
#39
I get it. I understand electricity. I am a master MECP tech. It just depends on what you are doing with it. Example, we would run electronics that cruise at 14.4 volts and low amperage. As soon as the voltage drops to 12, the amps shoot up. When I was a forklift tech, many moons ago, I would get a lot of calls to replace fuses because people would use the forklifts with too low of a voltage and it would raise the amperage and pop the fuse.