Oil Fuel Ratio
#1
I am running 30 percent nitro and 11 percent oil, I want to increase my oil percentage 2 percent, total of 13 percent. How much oil (ounces) do I have to add to one gallon of fuel? I am not sure but I come up with 2.5 oz, is this correct?Are there any fuel specialist out there?
#2
Using a prog called "Glowcalc" (glow fuel volume ratios):
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 11% = 0,11 US gallon = 14,08 US fluid Oz
Total 100%
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 13% = 0,13 US gallon = 16,64 US fluid Oz
Total 102%
Difference = 2,56
So you were correct
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 11% = 0,11 US gallon = 14,08 US fluid Oz
Total 100%
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 13% = 0,13 US gallon = 16,64 US fluid Oz
Total 102%
Difference = 2,56
So you were correct
#3
Using a prog called "Glowcalc" (glow fuel volume ratios):
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 11% = 0,11 US gallon = 14,08 US fluid Oz
Total 100%
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 13% = 0,13 US gallon = 16,64 US fluid Oz
Total 102%
Difference = 2,56
So you were correct
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 11% = 0,11 US gallon = 14,08 US fluid Oz
Total 100%
Methanol 59% = 0,59 US gallon = 75,52 US fluid Oz
Nitro 30% = 0,30 US gallon = 38,40 US fluid Oz
Oil 13% = 0,13 US gallon = 16,64 US fluid Oz
Total 102%
Difference = 2,56
So you were correct

#5
You can't have a bottle with 102% fuel in it! 
If you only add some oil, the methanol and nitro percent will drop.
1 gallon = 3,79 liter (l).
59% methanol = 3,79 * 0,59 = 2,2361 l.
30% nitro = 3,79 * 0,30 = 1,137 l.
11% oil = 3,79 * 0,11 = 0,4169 l.
Raise the total volume with 2,3%:
3,79 * 1,023 = 3,87717
13% of that volume is:
3,87717 * 0,13 = 0,50403
Oil you'll have to add:
0,50403 - 0,4169 = 0,08713 liter oil = 2,9462158 US fluid ounces
New percents:
Methanol = (2,2361 * 100) / 3,87717 = 57,67%
Nitro = (1,137 * 100) / 3,87717 = 29,33%
Oil = (0,50403 * 100) / 3,87717 = 13,00%
What oil will you add?
I bought 12 gallons of 16% fuel last year for close to nothing. To transform it to 25% nitro and still have the same oil percent, I'll have to add both nitro and oil.
Cheers

If you only add some oil, the methanol and nitro percent will drop.
1 gallon = 3,79 liter (l).
59% methanol = 3,79 * 0,59 = 2,2361 l.
30% nitro = 3,79 * 0,30 = 1,137 l.
11% oil = 3,79 * 0,11 = 0,4169 l.
Raise the total volume with 2,3%:
3,79 * 1,023 = 3,87717
13% of that volume is:
3,87717 * 0,13 = 0,50403
Oil you'll have to add:
0,50403 - 0,4169 = 0,08713 liter oil = 2,9462158 US fluid ounces
New percents:
Methanol = (2,2361 * 100) / 3,87717 = 57,67%
Nitro = (1,137 * 100) / 3,87717 = 29,33%
Oil = (0,50403 * 100) / 3,87717 = 13,00%
What oil will you add?
I bought 12 gallons of 16% fuel last year for close to nothing. To transform it to 25% nitro and still have the same oil percent, I'll have to add both nitro and oil.
Cheers
Last edited by Lille-bror; 12-15-2011 at 11:36 PM.
#7
You can't have a bottle with 102% fuel in it! 
If you only add some oil, the methanol and nitro percent will drop.
1 gallon = 3,79 liter (l).
59% methanol = 3,79 * 0,59 = 2,2361 l.
30% nitro = 3,79 * 0,30 = 1,137 l.
11% oil = 3,79 * 0,11 = 0,4169 l.
Raise the total volume with 2,3%:
3,79 * 1,023 = 3,87717
13% of that volume is:
3,87717 * 0,13 = 0,50403
Oil you'll have to add:
0,50403 - 0,4169 = 0,08713 liter oil = 2,9462158 US fluid ounces
New percents:
Methanol = (2,2361 * 100) / 3,87717 = 57,67%
Nitro = (1,137 * 100) / 3,87717 = 29,33%
Oil = (0,50403 * 100) / 3,87717 = 13,00%
What oil will you add?
I bought 12 gallons of 16% fuel last year for close to nothing. To transform it to 25% nitro and still have the same oil percent, I'll have to add both nitro and oil.
Cheers

If you only add some oil, the methanol and nitro percent will drop.
1 gallon = 3,79 liter (l).
59% methanol = 3,79 * 0,59 = 2,2361 l.
30% nitro = 3,79 * 0,30 = 1,137 l.
11% oil = 3,79 * 0,11 = 0,4169 l.
Raise the total volume with 2,3%:
3,79 * 1,023 = 3,87717
13% of that volume is:
3,87717 * 0,13 = 0,50403
Oil you'll have to add:
0,50403 - 0,4169 = 0,08713 liter oil = 2,9462158 US fluid ounces
New percents:
Methanol = (2,2361 * 100) / 3,87717 = 57,67%
Nitro = (1,137 * 100) / 3,87717 = 29,33%
Oil = (0,50403 * 100) / 3,87717 = 13,00%
What oil will you add?
I bought 12 gallons of 16% fuel last year for close to nothing. To transform it to 25% nitro and still have the same oil percent, I'll have to add both nitro and oil.
Cheers

Last edited by ramjesr; 12-16-2011 at 02:55 AM.
#8
I am running 30 percent nitro and 11 percent oil, I want to increase my oil percentage 2 percent, total of 13 percent. How much oil (ounces) do I have to add to one gallon of fuel? I am not sure but I come up with 2.5 oz, is this correct?Are there any fuel specialist out there?
#10
Ok you guys are right. I ran it the other day and did not have to tune the motor, it ran pretty good but it did run 15*hotter so about 245-250 degrees. I just wanted to ad (blendzall) to my fuel. I guess I will run 30%nitro w/9%oil and add 2.5 oz.of castor oil(blendzall) That would make it 11% oil. I am just experimenting with the oil. By the way I am running the OS .21XZB engine.
#14
I am just experimenting with oil. Byrons fuels are available in 30% nitro 11% oil. That is what I run, I did notice the engine ran better at 13% oil but 15degrees hotter.
#15
I think adding a very small ammount of castor oil is good. I wouldn't put 2 oz's in it. Probably 1/2 ounce. Most fuels with under 10% are pushing it. I like the 25% nitro 11% oil myself with a small ammount of castor just to make it perfect. especially during break in..I mix the 20% 16% with the 25% 11% sometimes. That works awesome for breakin......



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