telemtry roll input
Can someone tell me what the roll reading should be as I am having a hard time trying to inderstand Method B
circumference in inches = 7.693 (wheel diam is 2.44 inch or 62mm)
Spur 70 & Pin 37 = 1.89 ratio
Internal car ratio of 1.947
Fdr of 3.68
According to the manual I need to divide the circumference by the internal ratio. However it is somewhat confusing with the wording as at the start it requires either the intrnal ratio or to calculate the internal ratio (spur/pin)
So would this be 7.693/1.89=4.07 or 7.693/1.947 = 3.95
Can someone please pm or email me
Cheers