Servo torque - help me work this out.
I am not a physicist, but help me through this. I have a lot of questions.
I think I understand the basic of the torque ratings of a servo - how much it could lift at a certain distance from the output shaft (fulcrum). Is that rating then the breaking point of the servo?
For instance if it was 160oz-in rated servo, then with a 1 inch servo horn it could lift 10lbs.. Torque = Distance from fulcrum X Force applied, so at 2 inches it would be half the torque.
So I was thinking about a servo in a car, lets use the same one I described above. The servo would put out 10lbs of force through the linkages to the axle, but with a larger diameter wheel acting as a lever on that axle it would cut that force down depending on the size of the wheel. Lets say with a 1/8 scale wheel it would be by half. So does that mean that in a 1/8 scale buggy with the servo above, the front wheel hitting something with more than 5lbs (1/2 of the 10lbs at the servo) of force it would strip/break the servo, or at least push the servo motor backwards against it's force?
I also am not sure how much the servo saver can absorb either, or how much force is need to activate it. 10lbs in the example above does not seem like much force to engage a servo saver. Does the sever 'bottom out' eventually and continue to transmit the force, or once the saver is engaged no force goes to the servo? And if the saver is so effective, how do servos get stripped? Should the saver be 'tuned' to the spec of the servo?
I know many run with 170-250 oz-in servos successfully. So I'm sure my numbers are pretty error ridden, but is the idea is on the mark? An RC10B44.1 is less than 1/2 the weight of a RC8Be.
At the end of the day, are 400 oz-in servos what 1/8 scale cars should be starting with?