Well, if you can only find 50% nitro / 50% methanol... according to my simple math you would need:

58% of 100% Methanol
32% of 50% Methanol / 50% Nitro Mix
10% of Castor/Synthetic Oil


Would get you 16% nitro, 74% methanol and 10% oil.

0.32 * 0.5 nitro = 16% Of nitro that you want in your mixture
0.10 = Oil you want in the fuel

1 - 0.32 - 0.10 = Rest of what you need to add in methanol.


How do you get these percentages to actual values? Multiply the numbers by how much mixture you want, example:

Say you want to mix fuel for a gallon:
0.1 * 1 gallon = 0.1 gallon of Oil = 0.38L
0.32 * 1 gallon = 0.32 gallons of 50/50 mix = 1.21L
0.58 * 1 gallon = 0.58 gallons of pure methanol = 2.20L


Someone double check this please.