No they're not. The motor is a large inductor as well as a resistive load, and inductors resist spikes in current. Before the motor would get anywhere remotely close to drawing that much current, it has already rotated and will de-energise that phase and start energising the next phase. And even if it did, that's not representative of the power output of the motor. At 0 RPM, there is zero mechanical power output. Peak power output is at approximately half the no-load peak RPM.

I repeat. You cannot treat the motor as a purely resistive load. If you're going to use ohms law as a crude way to calculate the theoretical electrical load, you need to use the motors effective impedance (Z), not the stator resistance (R).