R/C Tech Forums - View Single Post - Icharger Discharge help
View Single Post
Old 06-03-2016 | 09:40 AM
  #7  
DirkW's Avatar
DirkW
Tech Elite
iTrader: (1)
 
Joined: Dec 2013
Posts: 2,904
From: Germany
Default

Originally Posted by SLOWINSLOWOUT
The icharger steps up the voltage to the load resistor, so you don't need low ohm resistors. But my resistor bank has an RT(total resistance) of 0.5ohms, so I suspect they are 5 100w 3ohm resistors.



5 10ohm resistors in parallel will give a total resistance of 2ohms, which would only put 4.2amp load on a 8.4v battery.

The formula to calculate RT of a parallel circuit is;

1/RT=1/R1+1/R2+1/R3+1/R4+1/R5

So for 10ohm resistors;

1/RT= 1/10+1/10+1/10+1/10+1/10;

1/RT=0.1+0.1+0.1+0.1+0.1;

1/RT=0.5;

RT=1/0.5;

RT=2ohms


Now we use Ohm's law to figure out current;

8.4v/2ohm=4.2amps

Here are some load resistor bank values;

5 10ohm resistors=2ohm
5 5ohm resistors=1ohm
5 4ohm resistors=0.8ohm
5 3ohm resistors=0.6ohm

Hope this helps

If you only put resistors of equal size in parallel, you can simplify that quite a bit:

For equal(!) resisitors in parallel, it's just the resistors' single rating divided by the number of resistors.

10/5 = 2.0 Ohm
5/5 = 1.0 Ohm
4/5 = 0.8 Ohm
3/5 = 0.6 Ohm
DirkW is offline