Originally Posted by
Chocula
For simplicity sake, assume you have two 10 lb/in springs. Assuming you apply a 10 force to one of the springs, it will compress 1 inch. Now stack them, and apply that same 10 lb force. The bottom spring now has 10 additional pounds on it so it compresses 1 inch. The top spring also has 10 additional pounds of force on it so it compresses 1 inch. This means your stack compressed 2 inches from 10 pounds of force which is a 5 lb/in equivalent.
This is why a longer spring that is wound exactly the same as a shorter one will be softer. Each coil deflects the same amount for a given load, but you have more coils on the longer spring so your total deflection is greater.
Using your example above and applying 10 pounds of force, you get the 1 inch from the 10 lbs/in spring and 0.5 inches for the 20 lbs/in spring for a total of 1.5 inches which you correctly calculated as 6.67 lbs/in.
Where dual rate springs react differently that simply using a single spring is when the softer spring exceeds its ability to compress linearly (overly simplified: it gets flattened and can't compress anymore), then any additional force is only compressing the stiffer spring. In the 10/20 lbs/in example you get 6.67 lbs/in until the 10 lb spring fully compresses, then you get 20 lbs/in. It is not quite that linear in the real world, but this should give you an understanding of what is going on.
-Chocula
Interesting the equation is the exact same for calculating the resistance of two parallel resistors. Thanks for this explanation, very enlightening, never really thought about the length of the spring changing its rate, makes sense though. More coils equals less each coil has to move for a given amount of spring compression. Seems like while everything is in pounds of resistance, its actually the length that is doing all the work in changing here.