You can't have a bottle with 102% fuel in it!

If you only add some oil, the methanol and nitro percent will drop.

1 gallon = 3,79 liter (l).
59% methanol = 3,79 * 0,59 = 2,2361 l.
30% nitro = 3,79 * 0,30 = 1,137 l.
11% oil = 3,79 * 0,11 = 0,4169 l.

Raise the total volume with 2,3%:
3,79 * 1,023 = 3,87717
13% of that volume is:
3,87717 * 0,13 = 0,50403
Oil you'll have to add:
0,50403 - 0,4169 = 0,08713 liter oil = 2,9462158 US fluid ounces

New percents:
Methanol = (2,2361 * 100) / 3,87717 = 57,67%
Nitro = (1,137 * 100) / 3,87717 = 29,33%
Oil = (0,50403 * 100) / 3,87717 = 13,00%

What oil will you add?


I bought 12 gallons of 16% fuel last year for close to nothing. To transform it to 25% nitro and still have the same oil percent, I'll have to add both nitro and oil.


Cheers