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Question about rotor strength
Assuming all other factors being equal, which of these rotors would have the least amount of drag brake effect:
12.0 x 7.25 x 25.3 12.0 x 5.0 x 23.0 |
Originally Posted by Cavi Mike
(Post 15987267)
Assuming all other factors being equal, which of these rotors would have the least amount of drag brake effect:
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Google can find answers
Muchmore Racing. Co., Ltd. But what does it say, they are only dimensions, it says nothing about the actual strength of the magnet |
Originally Posted by Cavi Mike
(Post 15987267)
Assuming all other factors being equal, which of these rotors would have the least amount of drag brake effect:
12.0 x 7.25 x 25.3 12.0 x 5.0 x 23.0 |
Originally Posted by trilerian
(Post 15987283)
Those rotors will have different amounts of magnetic material in them. If the gauss is the same per unit density of the material, then the 12.0 x 7.25 x 25.3 will have less gauss overall and should have less drag brake effect. Use area of a cylinder - area of the smaller cylinder to solve.
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Originally Posted by mrreet2001
(Post 15987297)
OP didn't say which factors are the same. If you put both on a rotor checker / Gauss meter and they read the same ... they should have the same drag effect.
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There is no gauss rating listed, they are only listed as having N35 composition.
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Originally Posted by Cavi Mike
(Post 15987309)
There is no gauss rating listed, they are only listed as having N35 composition.
EDIT: If you have a large open space you can probably get an idea from getting to full throttle and letting off and use a stop watch or measure the stopping distance. |
Originally Posted by mrreet2001
(Post 15987280)
If the Gauss value is the same ... the will have the same drag brake effect.
And there are not dozens of different compositions either, there are only a handful. So if I’m comparing two rotors made from the same compound but have differing lengths and mass, they will have different strengths. But maybe that really only applies to their saturation point when the core winding is fully electrified. So maybe since the diameter of them is the same, it’s possible they could have the same force against an idle core which means the length of them will determine the drag brake effect. But I don’t know. So I asked here thinking maybe someone else has already experimented with this. |
Originally Posted by trilerian
(Post 15987301)
Go back and read my post, I did put a qualifier in there...
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Originally Posted by Cavi Mike
(Post 15987317)
I’m not sure you understand how magnets are made. They start out completely unmagnetized, from a powder that is sintered in a die. Then they are put into a very powerful electromagnet that magnetizes them. The power of the magnetizer does not give them their ultimate strength, the composition of the magnet is what gives them their strength.
And there are not dozens of different compositions either, there are only a handful. So if I’m comparing two rotors made from the same compound but have differing lengths and mass, they will have different strengths. But maybe that really only applies to their saturation point when the core winding is fully electrified. So maybe since the diameter of them is the same, it’s possible they could have the same force against an idle core which means the length of them will determine the drag brake effect. But I don’t know. So I asked here thinking maybe someone else has already experimented with this. |
Originally Posted by mrreet2001
(Post 15987321)
Two rotors from the same manufacturer... made with the same process... out of the material ... to the same dimensions... with the same part number ... can and will have different overall Gauss readings.
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Originally Posted by trilerian
(Post 15987323)
It's funny really. Cause you just posted what I took the OP to mean by all other things being equal, ie, apple = apple, same company, dimensions, etc, same gauss. We both know they can be different by quite a bit, but that is the assumption to all other things being equal. Where you ran with all other things being equal was orange = apple, by saying rotors of completely different sizes would have the same gauss reading.
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Originally Posted by mrreet2001
(Post 15987325)
OP should have posted what was equal as all things can't be equal. Particularly given that Mike historically "seems" to know more than anyone trying to answer his questions.
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Originally Posted by Cavi Mike
(Post 15987350)
The irony.
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