When setting up an esc and calibrating it to transmitter most all instructions say set end points to 100. A lot of transmitters end points go to 150. What happens (positives and negatives) if you calibrate the esc with the endpoints at 150 instead of 100?

That’s a great question but i dont really understand the answer. i assume that the analog values from the esc fit into a 16bit register. The 16bit register runs through a scaler which is probably 16 bit as well and then lands in another 16 bit register that looks like -150 to +150 or -100 to + 100. Since the percentage of stroke is a whole number and is probably truncated are we just getting finer more points in the percent side of the calculation that get laid over the integer that represents analog position feedback (integer)?

I dont know the register sizes but the question should be the same whether its 10 or 16.

I can clarify my question if it was too much.

Thanks gents. Makes sense and appreciated.