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Old 01-24-2011, 12:01 PM
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Questions?? Will this work??????

Hello all I was looking to put headlights in drift car. Since I don't want to spend $$$$ on buying a pre-made kit, i'm going to make my own. So my question is, will this set up work???

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Old 01-24-2011, 01:07 PM
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Good day!

No, that will not work. LED's need a current limmiting resitor or they will fail as soon as you put power to them. It has been a while but I will try to draw up a schematic for you and post it a little later.
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Old 01-24-2011, 01:30 PM
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I will need to know what the voltage drop across the type of LED you are going to use or a spec sheet for the led you are going to use (they are not all the same).
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Old 01-24-2011, 04:02 PM
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Originally Posted by BCbud
I will need to know what the voltage drop across the type of LED you are going to use or a spec sheet for the led you are going to use (they are not all the same).
Oh man, that would be awesome!! Thanks!! I don't mean to sound uneducated, but im not sure what you mean. The only info I can really give you is this: Would like the LED's to shine nice and bright, am either looking at a 9V battery, or two AAA for a power source ( which ever you think is better) , and the LED's are 3.6 Volt, 20mA, 1100cd.
That is all I can really tell you. I hope that is okay. Also, are those LED's good enough for what im going to use them for??

Thanks again chap!
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Old 01-24-2011, 04:10 PM
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I had a brain fart, you already told me that lol! But I will need to know how many LED's you are going to use. Your picture only shows 2 but are you going to install lights front and rear?
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Old 01-24-2011, 05:02 PM
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Originally Posted by BCbud
I had a brain fart, you already told me that lol! But I will need to know how many LED's you are going to use. Your picture only shows 2 but are you going to install lights front and rear?
Lol, no problem. No only in the front. Im just going to run 2 head lights because I dont have light buckets for the rear. So just 2 LED head lights.
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Old 01-24-2011, 05:16 PM
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OK, I was just looking at your drawing and it says 3.2V but you are telling me 3.6, I just want to make shure witch votage LED's you are planning to use?
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Old 01-24-2011, 05:41 PM
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Originally Posted by BCbud
OK, I was just looking at your drawing and it says 3.2V but you are telling me 3.6, I just want to make shure witch votage LED's you are planning to use?
Im sorry, they are indeed 3.6 . The drawing is wrong ( sorry!)
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Old 01-24-2011, 06:35 PM
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Good day!

This should work for you. There are other ways of doing it but this way if one LED fails, the other will still work.
Attached Thumbnails Will this work??????-scan0001.jpg  
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Old 01-24-2011, 07:41 PM
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Why use a separate 9V battery when you already have 5-6V available at the RX? The schematic will still work, just need to adjust the resistor value and plug into an open RX channel. The amount of current is quite small, and would be negligible as far as affecting your runtime.

Last edited by simplechamp; 01-24-2011 at 07:51 PM.
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Old 01-26-2011, 03:50 PM
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Dude just buy a LED kit!

I just won one on ebay auction for $10 shipped
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Old 01-26-2011, 08:45 PM
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Originally Posted by BCbud
Good day!

This should work for you. There are other ways of doing it but this way if one LED fails, the other will still work.

That you so much for that chap! I really appreciate it.
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Old 01-26-2011, 08:46 PM
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Originally Posted by sliding_josh
Dude just buy a LED kit!

I just won one on ebay auction for $10 shipped

Because I would not be learning anything that way brah.
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Old 01-27-2011, 08:53 AM
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I know some ESC's can support brake lighting if that is an option for you?

The Tekin G11Pro does that if you wanted to look into it.
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Old 01-27-2011, 05:44 PM
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Originally Posted by BCbud
Good day!

This should work for you. There are other ways of doing it but this way if one LED fails, the other will still work.
Looks to me like your running 9V through each LED only rated for 3.6V. They don't share voltage in a parallel circuit. Also your Ohm's law formula is the calculation for total resistance in a series circuit when you have clearly made a parallel circuit. Try again.
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