Modding Dischargers
#31
Originally Posted by XrayFK
Diodes have a forward voltage drop meaning that the voltage has to be so high for current to pass through. If the voltage is less than that limit then no current will pass through the diode.
#33
Originally Posted by XrayFK
Nothing, the voltage drop is the same (rated, actual value may vary) The amp ratings are exactly that, how much current the diode is rated at.
#34
Cutoff voltage will vary depending on diode type, but standard rectifier diodes are generally 0.7v . This is the cut-off Voltage.
I thing the current is worked out like this( sticking my neck out here )
1.2v(cell)- 0.7v(diode)= 0.5v drop over the resistor.
Ohms law= I(current)= V/R so,
I= 0.5v/0.4r= 1.25A
Now, power(watts) = VxI so, 0.5x 1.25=0.625w so a 1watt 0.5 ohm resistor should be sufficient
Now I'm no expert so someone tell me if i'm wrong
I thing the current is worked out like this( sticking my neck out here )
1.2v(cell)- 0.7v(diode)= 0.5v drop over the resistor.
Ohms law= I(current)= V/R so,
I= 0.5v/0.4r= 1.25A
Now, power(watts) = VxI so, 0.5x 1.25=0.625w so a 1watt 0.5 ohm resistor should be sufficient
Now I'm no expert so someone tell me if i'm wrong
#35
Tech Master
iTrader: (1)
Originally Posted by zax
if i am using 0.4ohm resistor and a 5A diode on each cell..what is the discharging current and the cut off voltage?
Whatever the cell voltage, it directly affects the discharge current. So at 1.2v, the current is 1.2/.4= 3A. The cells will equalize closer to 0.6v if you leave them on long enough, and that rate would be 1.5A
If the diode has a forward voltage of 0.7v, that doesn't necessarily mean that anything under that has no flow. The current to voltage graph of a diode is extremely exponential before and after the drop point. So anything above 0.7v goes up so high that pretty much the same amount will pass through. Under 0.7v the current decreases just as quickly, but does not go immediately to zero. I hope I've explained that correctly/clearly. Either way, diodes aren't perfectly accurate anyways, so small but noticeable variances between even the same model numbers exist.
#36
with all that said.. ill think ill save up for a novak smart tray (or anything like it). im no electrician and what i currently have is a trinity realtime 2.5 tray. im beginning to stack up on IB cells, and as i have read, they dont want to be discharged to 0 volts like the GP cells.
#37
Tech Adept
iTrader: (1)
I still recommend EQUALIZING the cells at a low current setting...because then you get real equalization. The lower the current setting, the better the equalization.
#38
the teamwave lightning takes overnight to get it to 0.7volts at the slowest setting.
#39
Originally Posted by XrayFK
loopedeloop has the correct equation, but is slightly off.
Whatever the cell voltage, it directly affects the discharge current. So at 1.2v, the current is 1.2/.4= 3A. The cells will equalize closer to 0.6v if you leave them on long enough, and that rate would be 1.5A
If the diode has a forward voltage of 0.7v, that doesn't necessarily mean that anything under that has no flow. The current to voltage graph of a diode is extremely exponential before and after the drop point. So anything above 0.7v goes up so high that pretty much the same amount will pass through. Under 0.7v the current decreases just as quickly, but does not go immediately to zero. I hope I've explained that correctly/clearly. Either way, diodes aren't perfectly accurate anyways, so small but noticeable variances between even the same model numbers exist.
Whatever the cell voltage, it directly affects the discharge current. So at 1.2v, the current is 1.2/.4= 3A. The cells will equalize closer to 0.6v if you leave them on long enough, and that rate would be 1.5A
If the diode has a forward voltage of 0.7v, that doesn't necessarily mean that anything under that has no flow. The current to voltage graph of a diode is extremely exponential before and after the drop point. So anything above 0.7v goes up so high that pretty much the same amount will pass through. Under 0.7v the current decreases just as quickly, but does not go immediately to zero. I hope I've explained that correctly/clearly. Either way, diodes aren't perfectly accurate anyways, so small but noticeable variances between even the same model numbers exist.
#40
Originally Posted by sup
with all that said.. ill think ill save up for a novak smart tray (or anything like it). im no electrician and what i currently have is a trinity realtime 2.5 tray. im beginning to stack up on IB cells, and as i have read, they dont want to be discharged to 0 volts like the GP cells.
#41
Tech Master
iTrader: (1)
Originally Posted by sup
with all that said.. ill think ill save up for a novak smart tray (or anything like it). im no electrician and what i currently have is a trinity realtime 2.5 tray. im beginning to stack up on IB cells, and as i have read, they dont want to be discharged to 0 volts like the GP cells.
#42
Tech Master
iTrader: (1)
Originally Posted by Alfalfameister
So the Tekin Battery Doctor is a good tray then, yes? I think it draws at 2 amps all the way down to .9 volts or something, and much lower current that s_l_o_w_l_y brings it down to .5 volts (took several hours from .7 to .5 volts).
#43
killingtime & xrayFK, quite confusing actually for individuals like me that does not know a thing about electronics. but, its a good read. with what xrayfk explained, all i need now is the guts to do it myself. ill just backread a little and find the parts i need from the local electronics supply. will see, i might get inspired to do this project this weekend. again, thanks a lot guys for your input.
#44
so anyone know if its possible to get diodes to get the zero-thirty to cut off at 0.95v/cell?
#45
let us know how it works for you sup. I'll be trying it out on my Integy Zero-6S and Zero-6M trays.