Originally Posted by
niznai
You're right, my mistake.
Still, that doesn't mean a higher resistor will heat more at the same voltage.
If it's in a typical electrical circuit of course it will heat more if you increase the resistance sufficiently and the current draw remains constant (which is how heat is calculated). It has to:
Joules First Law
Heat (Q) = Current squared (I^2) x Resistance (R) x Time (T)
"
Where Q is the heat generated by a constant current I flowing through a conductor of electrical resistance R, for a time t."
Wikipedia
It's really that simple. Short circuit a battery with different gauge wires, the higher resistance (thinner) wires will heat up quicker. Why? Because the higher level of resistance requires the charges to travel faster through the wire, generating more heat.
If there was not a perceptible change in temp - because that's entirely plausible - it's not explained by your logic either. The explanation is that in these cases, the additional resistance has made no real-world difference to the overall efficiency of the circuit so there's no perceptible change in heat output.
When we talk about heat, we keep current constant. Always.
Myth Busted!