Originally Posted by Cabledawg

I posted this earlier with no responses. At least tell me if there is another forum or thread this needs to go to and I will post it there.

Can someone help me to see if my thinking and/or math is correct.

I have a recently purchased 3.0 with a Castle Mamba 2 and Neu 2200KV. I took it to the track Sunday and really had a great time. It was my first time racing in 15 years. I have been into planes during that time.

I have a lot of 6S batteries from my planes and only had 2 4S 4500mah to run in the buggy. I want to use my 6S batteries. In doing so, I want to keep the same amount of power with less amps. It should be the same principle as my planes....ie....if I go from 4S to 6S and to a smaller prop, I end up with the same amout of power with less amp draw which is less heat and more efficient.
This is a measureable amount and not theory.

Here are the numbers and I am not positive about everything.1.The stock system is 2200KV x 14.8V = 32,560rpms (no load)
2.My pinion and gear is 15/43 x 3.3 (drive ratio) = 9.46 (Final drive ratio)
3.32,560 / 9.46 = 3,441 (rpm's for 1 revolution of wheel)

So if I can find a 6S system close to 3,441....it should be the same amount of power / watts.
1.2200KV x 22.2V = 48,840
2.Pinion Spur is 11/45 for a final drive of 13.487
3.48,840 / 13.487 = 3618 (a 10 tooth pinion is 3288)

I realize this is all no load and perfect conditions, but if I do change to 6S and put a wattmeter on it, I should be close to what I had on 4S.......am I close?