Originally Posted by Deves
What is the calculation for figuring the drive ratio with the 18 tooth pulley?
I know that spur divided by pinion times the transmission drive = the Fdr but how do you figure the transmission drive ratio with the different center pulleys?
I don't know if I'm making myself clear or not.....does anybody know what i'm trying to say here???
If you divide the big pulley through the small pulley + spur gear through the pinion gear you have your reduction rate
39 belt pulley/18 pulley = 2.166
108 spurgear/28 pinion = 3.857
This is what you looking for i hope ?